Posted by Collin on .
(square root 5) times (square root 12)
x > 0, (square root x) times (square root 3x)

Math 
bobpursley,
ON the first:
sqrt12= sqrt(4*3)=2sqrt3 now use that.
On the second:
sqrtx*sqrt3x= xsqrt3
Posted by Collin on .
(square root 5) times (square root 12)
x > 0, (square root x) times (square root 3x)
ON the first:
sqrt12= sqrt(4*3)=2sqrt3 now use that.
On the second:
sqrtx*sqrt3x= xsqrt3