Posted by MW on Sunday, September 6, 2009 at 11:59pm.
I have a parametrization for a curve..
x = 5 cos t
y = 2 sin t
I made the graph...
its initial point is (3,0), and curves up and to the left.
So, I have my points for the graph. How do I come up with the cartesian equation?

Calculus  drwls, Monday, September 7, 2009 at 3:28am
(x/5)^2 + (y/2)^2 = 1
is the Cartesian form.
This is the equation of an ellipse centered at the origin.
(3,0) cannot be on the curve, because when y=0, t = 0 or pi, and that requires that x = 5 or 5.