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Posted by on Sunday, September 6, 2009 at 11:59pm.

I have a parametrization for a curve..

x = 5 cos t
y = 2 sin t

I made the graph...
its initial point is (3,0), and curves up and to the left.

So, I have my points for the graph. How do I come up with the cartesian equation?

  • Calculus - , Monday, September 7, 2009 at 3:28am

    (x/5)^2 + (y/2)^2 = 1
    is the Cartesian form.

    This is the equation of an ellipse centered at the origin.

    (3,0) cannot be on the curve, because when y=0, t = 0 or pi, and that requires that x = 5 or -5.

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