Thursday

August 21, 2014

August 21, 2014

Posted by **MW** on Sunday, September 6, 2009 at 11:59pm.

x = 5 cos t

y = 2 sin t

I made the graph...

its initial point is (3,0), and curves up and to the left.

So, I have my points for the graph. How do I come up with the cartesian equation?

- Calculus -
**drwls**, Monday, September 7, 2009 at 3:28am(x/5)^2 + (y/2)^2 = 1

is the Cartesian form.

This is the equation of an ellipse centered at the origin.

(3,0) cannot be on the curve, because when y=0, t = 0 or pi, and that requires that x = 5 or -5.

**Related Questions**

Calculus - MathMate Please help - ok, i tried to do what you told me but i cant ...

Math - Consider the paraboloid z=x^2+y^2. The plane 3x-2y+z-7=0 cuts the ...

Math - Consider the paraboloid z=x^2+y^2. The plane 3x-2y+z-7=0 cuts the ...

calculus - Find complete length of curve r=a sin^3(theta/3). I have gone thus- (...

TRIG! - Posted by hayden on Monday, February 23, 2009 at 4:05pm. sin^6 x + cos^6...

Math - Calculus - The identity below is significant because it relates 3 ...

Math - Eliminate the parameter and write the corresponding rectangular equation ...

calculus - Find the points on the curve y= (cos x)/(2 + sin x) at which the ...

tigonometry - expres the following as sums and differences of sines or cosines ...

Mathematics - Trigonometric Identities - Let y represent theta Prove: 1 + 1/tan^...