Posted by MW on Sunday, September 6, 2009 at 11:59pm.
I have a parametrization for a curve..
x = 5 cos t
y = 2 sin t
I made the graph...
its initial point is (3,0), and curves up and to the left.
So, I have my points for the graph. How do I come up with the cartesian equation?

Calculus  drwls, Monday, September 7, 2009 at 3:28am
(x/5)^2 + (y/2)^2 = 1
is the Cartesian form.
This is the equation of an ellipse centered at the origin.
(3,0) cannot be on the curve, because when y=0, t = 0 or pi, and that requires that x = 5 or 5.
Answer This Question
Related Questions
 calculus  Find the points on the curve y= (cos x)/(2 + sin x) at which the ...
 Calculus  MathMate Please help  ok, i tried to do what you told me but i cant ...
 calculus  Find complete length of curve r=a sin^3(theta/3). I have gone thus (...
 Calculus  a)The curve with equation: 2y^3 + y^2  y^5 = x^4  2x^3 + x^2 has ...
 TRIG!  Posted by hayden on Monday, February 23, 2009 at 4:05pm. sin^6 x + cos^6...
 Math Calc 1  1. At what point does the normal line to the curve x^2  XY + Y^2...
 calculus  1. Which of the following expressions is the definition of the ...
 Calc  1. At what point does the normal line to the curve x^2  XY + Y^2 = 3 at ...
 Math  Consider the paraboloid z=x^2+y^2. The plane 3x2y+z7=0 cuts the ...
 Math  Consider the paraboloid z=x^2+y^2. The plane 3x2y+z7=0 cuts the ...
More Related Questions