Posted by **Ashley** on Sunday, September 6, 2009 at 8:51pm.

Hello, I have tried solving this using the rational roots theorem and none of the roots seem to be working. I'm trying to figure out where I went wrong.

3x^3 -2x^2 - 7x - 4 = 0

- Pre-Calculus -
**Reiny**, Sunday, September 6, 2009 at 11:30pm
you are right, it does not factor over the rational numbers.

here is a webpage that solves cubics for you, just enter the constants

it gave me 1 irrational root and 2 complex roots.

- Pre-Calculus -
**Ashley**, Monday, September 7, 2009 at 12:07am
Thanks for the help. However, I don't see the webpage you were speaking of.

- Pre-Calculus -
**Reiny**, Monday, September 7, 2009 at 12:10am
how silly of me

http://www.1728.com/cubic.htm

- Pre-Calculus -
**Ashley**, Monday, September 7, 2009 at 12:13am
Thanks!

## Answer This Question

## Related Questions

- Pre-Calc-Please check - Is this correct? Using Rational Roots Theorem, list all...
- Pre-Calc-Please check - I have three questions: 1. What is the remainder of (x^3...
- Math - How to factor x^3 - 3x^2 + 4 =0 Use D'Alembert's Rational Roots Theorem. ...
- algebra - using the rational root theorem to list all possible rational roots of...
- Math - Roots Ok, what about roots? Roots of polynomials? Square roots? Cube ...
- Pre Calculus - So I only have 3 homework questions left and I can't seem to ...
- ALGEBRA 2 - Use the Rational Root Theorem to list all possible rational roots ...
- pre-calculus - partial fraction; use the rational roots theorem to factor ...
- Pre Calc - Write a quartic function that has roots that are 3+5i, -4 and 7 and f...
- Precalculus - "Show that x^6 - 7x^3 - 8 = 0 has a quadratic form. Then find the ...

More Related Questions