Posted by Ashley on Sunday, September 6, 2009 at 8:51pm.
Hello, I have tried solving this using the rational roots theorem and none of the roots seem to be working. I'm trying to figure out where I went wrong.
3x^3 2x^2  7x  4 = 0

PreCalculus  Reiny, Sunday, September 6, 2009 at 11:30pm
you are right, it does not factor over the rational numbers.
here is a webpage that solves cubics for you, just enter the constants
it gave me 1 irrational root and 2 complex roots.

PreCalculus  Ashley, Monday, September 7, 2009 at 12:07am
Thanks for the help. However, I don't see the webpage you were speaking of.

PreCalculus  Reiny, Monday, September 7, 2009 at 12:10am
how silly of me
http://www.1728.com/cubic.htm

PreCalculus  Ashley, Monday, September 7, 2009 at 12:13am
Thanks!
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