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August 30, 2014

August 30, 2014

Posted by **vera** on Sunday, September 6, 2009 at 5:23pm.

Do not understand this question.

- math -
**MathMate**, Sunday, September 6, 2009 at 5:37pmThe usual equation of a straight line with a know slope is

y = mx + b

where m is the slope, and

b is the y-intercept.

The question provides you with the slope m=2 and a point P(5,0) through which the line passes.

The equation of a line passing through a point P1(x1,y1) with a slope of m is

(y-y1)=m(x-x1)

In effect, what you are required to do is to substitute the given values of m and (x1,y1) into the above equation, and simplify the resulting equation into the form y=mx+b.

Unfortunately the form of the equation y=mx+b does not work when the line is parallel to the y-axis when the equation takes the form x=a, or when the line is parallel to the x-axis, then it takes the form y=b, where a and b are the x and y-intercepts respectively.

Give the problem a try and post your answer for verification if necessary.

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