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August 27, 2014

August 27, 2014

Posted by **trig** on Sunday, September 6, 2009 at 5:06pm.

(def of tan theta = a^-1 o)a = o

opposite = adjacent tan theta

written with respect to the first angle

opposite = (adjacent 1 + adjacent 2) tan theta one

were adjacent 1 is the 50 feet

written for the second angle

opposite = adjacent 2 tan theta two

set them equal to each other

(adjacent 1 + adjacent 2) tan theta one = adjacent 2 tan theta two

distripute

adjacent 1 tan theta one + adjacent 2 tan theta one = adjacent 2 tan theta two

subtract from both sides

adjacent 1 tan theta one = adjacent 2 tan theta two - adjacent 2 tan theta one

factor or whatever

adjacent 1 tan theta one = adjacent 2 (tan theta two - tan theta one)

muliply by inverse to solve for adjacent 2

(adjacent 1 tan theta one = adjacent 2 (tan theta two - tan theta one)) ((tan theta two - tan theta one)^-1

adjacent two = (tan theta two - tan theta one)^-1 adjacent 1 tan theta one

plug and chug for adjacent two

adjacent two = (tan 32 degrees - tan 40 degrees)^-1 (50 ft) tan theta 40 degrees

I got negative 195.8 feet?

- trig -
**MathMate**, Sunday, September 6, 2009 at 5:16pm - trig -
**stat**, Sunday, September 6, 2009 at 5:18pmthat would be the image i put up...

i don\'t understand???

- trig -
**MathMate**, Sunday, September 6, 2009 at 5:19pmIf you look at the figure, you will see that θ1 should be smaller than θ2, but you have labelled θ1=40, and θ2=32.

Perhaps the two values have been inverted and perhaps that is the source of your problem.

Could you please check and let us know?

- trig -
**MathMate**, Sunday, September 6, 2009 at 5:21pmYes, I translated the link so that other people could see your image without having to go through the hassle I had to.

- trig -
**stat**, Sunday, September 6, 2009 at 5:21pmhmmmm ok i\'ll try and see what i get thanks

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