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If you were to dissolve 14.00 grams of salicylic acid in enough water to make 400.00 mL of solution, what is the molarity of the final solution?

i did M = moles/L
so .1014 mol/.4000L = .2535 M

is this correct??

The next part of the question is

Now you take 50.00 mL of this solution and dilute it to 250.00 mL. What is the molarity.

I need help with this part. thankss

  • chemistry -

    I get 0.2534 M. The difference is that you rounded the 14.00/138.12 to 0.1014 whereas I left the number (0.10136) in the calculator before dividing by the 0.4000.

  • chemistry -

    what about the other part?

  • chemistry -

    Just use M1V1 = M2V2

  • chemistry -


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