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April 1, 2015

April 1, 2015

Posted by **Ash** on Sunday, September 6, 2009 at 1:10pm.

Ok, thanks. Now I'm trying to multiply out and having some difficulty. I am getting 4x^3-70x^2+304x = 175 which I'm not sure how to work with

- PRE CALCULUS -
**MathMate**, Sunday, September 6, 2009 at 1:36pmI agree it is a little difficult to solve unless you have learned Newton's method. If not, you can solve it by the bisection method, which is to evaluate the function using trial values of x until the function evaluates to 175.

I will give you a kick-start.

Let

f(x)= x(16-2x)(19-2x)

and knowing that the solution is around 0.68, we try

f(0.6)=0.6(16-2*0.6)(19-2*0.6)=158.064

f(0.7)=179.872

f(0.65)=169.124

So the next tries should lie between 0.65 and 0.7.

Keep on trying until you get a solution to within 1 or two decimals.

- PRE CALCULUS -
**MathMate**, Sunday, September 6, 2009 at 1:50pmHere is a graph of the function f(x).

http://i263.photobucket.com/albums/ii157/mathmate/Ash.png

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