Posted by Ash on Sunday, September 6, 2009 at 1:10pm.
I agree it is a little difficult to solve unless you have learned Newton's method. If not, you can solve it by the bisection method, which is to evaluate the function using trial values of x until the function evaluates to 175.
I will give you a kick-start.
Let
f(x)= x(16-2x)(19-2x)
and knowing that the solution is around 0.68, we try
f(0.6)=0.6(16-2*0.6)(19-2*0.6)=158.064
f(0.7)=179.872
f(0.65)=169.124
So the next tries should lie between 0.65 and 0.7.
Keep on trying until you get a solution to within 1 or two decimals.
Here is a graph of the function f(x).
http://i263.photobucket.com/albums/ii157/mathmate/Ash.png
Related Questions
Pre-Calc - I am having a great deal of difficulty with this problem. An open box...
math - i am having a minor difficulty i've been stuck for over an hour and ...
Algebra - Two more Algebra questions : Having some difficulty with these. ...
Calculus - relative extrema x^4-2x^2+5 so far I know how to find the derivative ...
TRIG! - Posted by hayden on Monday, February 23, 2009 at 4:05pm. sin^6 x + cos^6...
Algebra - I have some problems that I am having trouble with and I have some ...
bobpursley,math - about this problem , I figured it out and i did get the answer...
PRE-CALCULUS - AN OPEN BOX IS FORMED BY CUTTING SQUARES OUT OF A PIECE OF ...
algebra - solve the polynomial y=2x^2-4x+1 For Further Reading algebra - Reiny, ...
Pre-Cal - I'm trying to do this identities homework and i can't figure ...
For Further Reading
