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Posted by on Sunday, September 6, 2009 at 12:31pm.

AN OPEN BOX IS FORMED BY CUTTING SQUARES OUT OF A PIECE OF CARDBOARD THAT IS 16 FT BY 19 FT AND FOLDING UP THE FLAPS. WHAT SIZE CORNER SQUARES SHOULD BE CUT TO YEILD A BOX THAT HAS A VOLUME OF 175 CUBIC FEET

  • PRE-CALCULUS - , Sunday, September 6, 2009 at 12:52pm

    Let the side of the square to be cut out be x ft.
    The volume of the resulting box is then
    V = x(16-2x)(19-2x) = 175 ft³
    You can solve the equation by trial and error, there should be a root around x=0.68 ft.

  • PRE-CALCULUS - , Sunday, September 6, 2009 at 1:12pm

    V = x(16-2x)(19-2x) = 175 ft³

    Ok, thanks. Now I'm trying to multiply out and having some difficulty. I am getting 4x^3-70x^2+304x = 175 which I'm not sure how to work with

  • PRE-CALCULUS - , Sunday, September 6, 2009 at 5:43pm

    See response of follow-up post:
    http://www.jiskha.com/display.cgi?id=1252257020

  • PRE-CALCULUS - , Saturday, June 28, 2014 at 6:14am

    2.885

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