Posted by **ASHLEY** on Sunday, September 6, 2009 at 12:31pm.

AN OPEN BOX IS FORMED BY CUTTING SQUARES OUT OF A PIECE OF CARDBOARD THAT IS 16 FT BY 19 FT AND FOLDING UP THE FLAPS. WHAT SIZE CORNER SQUARES SHOULD BE CUT TO YEILD A BOX THAT HAS A VOLUME OF 175 CUBIC FEET

- PRE-CALCULUS -
**MathMate**, Sunday, September 6, 2009 at 12:52pm
Let the side of the square to be cut out be x ft.

The volume of the resulting box is then

V = x(16-2x)(19-2x) = 175 ft³

You can solve the equation by trial and error, there should be a root around x=0.68 ft.

- PRE-CALCULUS -
**Ashley**, Sunday, September 6, 2009 at 1:12pm
V = x(16-2x)(19-2x) = 175 ftÂ³

Ok, thanks. Now I'm trying to multiply out and having some difficulty. I am getting 4x^3-70x^2+304x = 175 which I'm not sure how to work with

- PRE-CALCULUS -
**MathMate**, Sunday, September 6, 2009 at 5:43pm
See response of follow-up post:

http://www.jiskha.com/display.cgi?id=1252257020

- PRE-CALCULUS -
**Anonymous**, Saturday, June 28, 2014 at 6:14am
2.885

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