Posted by ASHLEY on Sunday, September 6, 2009 at 12:31pm.
AN OPEN BOX IS FORMED BY CUTTING SQUARES OUT OF A PIECE OF CARDBOARD THAT IS 16 FT BY 19 FT AND FOLDING UP THE FLAPS. WHAT SIZE CORNER SQUARES SHOULD BE CUT TO YEILD A BOX THAT HAS A VOLUME OF 175 CUBIC FEET

PRECALCULUS  MathMate, Sunday, September 6, 2009 at 12:52pm
Let the side of the square to be cut out be x ft.
The volume of the resulting box is then
V = x(162x)(192x) = 175 ft³
You can solve the equation by trial and error, there should be a root around x=0.68 ft. 
PRECALCULUS  Ashley, Sunday, September 6, 2009 at 1:12pm
V = x(162x)(192x) = 175 ftÂ³
Ok, thanks. Now I'm trying to multiply out and having some difficulty. I am getting 4x^370x^2+304x = 175 which I'm not sure how to work with 
PRECALCULUS  MathMate, Sunday, September 6, 2009 at 5:43pm
See response of followup post:
http://www.jiskha.com/display.cgi?id=1252257020 
PRECALCULUS  Anonymous, Saturday, June 28, 2014 at 6:14am
2.885