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college/earth science

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if unsaturated air at 23 degree celsius were to rise, what would its temperature be at 500 meters?

  • college/earth science - ,

    23 C = 300 K

    The air density at the initial altitude (assuming sea level) is (29 g)/(24.6 *10^3 cm^3) = 1.18*10^-3 g/cm^3 = 1.18 kg/m^3

    The pressure decrease after a 500 m elevation increase is
    (density)*g*500 m = 5780 N/m^2
    The pressure decrease factor is
    (Po - 5780)/Po = 0.990, where
    Po is the sea level atmospheric pressure.

    Assume an adiabatic isentropic change in air temperature as the pressure decreases, with an air specific heat ratio (gamma) of g = 1.4.
    (T2/T1) = (P2/P1)^[(g-1)/g]
    = 0.990^(0.286) = 0.997
    T2 = 299 K = 22 C

    If you need a more complete explanation, see
    http://farside.ph.utexas.edu/teaching/sm1/lectures/node56.html

    I may have made a computing error somewhere along the way. You should verify the calculations

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