if unsaturated air at 23 degree celsius were to rise, what would its temperature be at 500 meters?

23 C = 300 K

The air density at the initial altitude (assuming sea level) is (29 g)/(24.6 *10^3 cm^3) = 1.18*10^-3 g/cm^3 = 1.18 kg/m^3

The pressure decrease after a 500 m elevation increase is
(density)*g*500 m = 5780 N/m^2
The pressure decrease factor is
(Po - 5780)/Po = 0.990, where
Po is the sea level atmospheric pressure.

Assume an adiabatic isentropic change in air temperature as the pressure decreases, with an air specific heat ratio (gamma) of g = 1.4.
(T2/T1) = (P2/P1)^[(g-1)/g]
= 0.990^(0.286) = 0.997
T2 = 299 K = 22 C

If you need a more complete explanation, see
http://farside.ph.utexas.edu/teaching/sm1/lectures/node56.html

I may have made a computing error somewhere along the way. You should verify the calculations

To determine the temperature of unsaturated air as it rises to a certain altitude, we need to consider the decrease in temperature with increasing altitude, known as the lapse rate. The standard atmospheric lapse rate is approximately 6.5 degrees Celsius per 1000 meters (or 3.6 degrees Fahrenheit per 1000 feet).

Therefore, we can calculate the temperature of unsaturated air at 500 meters by using the lapse rate:

1. Determine the lapse rate: The standard lapse rate is 6.5 degrees Celsius per 1000 meters.
2. Calculate the change in temperature: Multiply the lapse rate by the change in altitude (500 meters / 1000 meters) to get the change in temperature at that altitude.
Change in temperature = Lapse rate x (Change in altitude / 1000)
Change in temperature = 6.5 degrees Celsius per 1000 meters x (500 meters / 1000 meters)
Change in temperature = 6.5 degrees Celsius per 2
Change in temperature = 3.25 degrees Celsius
3. Calculate the final temperature: Subtract the change in temperature from the initial temperature to get the final temperature.
Final temperature = Initial temperature - Change in temperature
Final temperature = 23 degrees Celsius - 3.25 degrees Celsius
Final temperature = 19.75 degrees Celsius

Therefore, at an altitude of 500 meters, the temperature of the unsaturated air would be approximately 19.75 degrees Celsius.