Homework Help: physics

Posted by Nick on Friday, September 4, 2009 at 12:42am.

(a) If the maximum acceleration that is tolerable for passengers in a subway train is 1.52 m/s2 and subway stations are located 1030 m apart, what is the maximum speed a subway train can attain between stations?

b)what is the travel time between stations?

c)If a subway train stops for 20 s at each station, what is the maximum average speed of the train, from one start-up to the next?

physics - Damon, Friday, September 4, 2009 at 4:27am
Divide the problem in half, accelerate and deaccelerate.
half distance = 515
515 = (1/2)(1.52) t^2
that gives you half the time
v = 0 + 1.52 t^2
total time = 2 t + 20
v average = 1030/total time
physics - Nick, Friday, September 4, 2009 at 7:42am
thanks damon

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