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October 24, 2014

October 24, 2014

Posted by **Stacy** on Thursday, September 3, 2009 at 10:36pm.

f(x) = e^x/5, [0,5]

- Calculus -
**MathMate**, Friday, September 4, 2009 at 12:13amyou are looking at dividing the definite integral of f(x) from 0 to 5 by the length of the interval, namely (5-0)=5.

∫(1/5)e^{x}dx

=(1/5)[e^{x}] from 0 to 5

=(1/5)(e^{5}-e^{0})

=(1/5)(148.413-1)

=29.483

The average over the interval

=29.483/5

=5.8965

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