Posted by Nick on Wednesday, September 2, 2009 at 11:44pm.
First you must change 56 km/h to m/s. In m/s the Initial Velocity is 15.56 m/s. Next use the equation:
S = ViT + (1/2)at^2 and solve for a
21 = (15.56)(2.17) + (1/2)(a)(2.17)^2
a = -5.42 m/s^2
Now that you have the acceleration you can solve for the final velocity using either:
Vf = Vi + at ---or--- Vf^2 = Vi^2 + 2as
Vf = 15.56 + (-5.42)(2.17) = 3.8 m/s
or
Vf^2 = 15.56^2 + 2(-5.42)(21) = 3.8 m/s
As you can see each equation gave the same answer. Overall your answers would be:
a.) -5.42 m/s^2
b.) 3.8 m/s
thanks
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