Posted by Nick on .
A car traveling 56 km/h is 21.0 m from a barrier when the driver slams on the brakes. The car hits the barrier 2.17 s later.
a)What was the car's constant deceleration before impact?
b)How fast was the car traveling at impact?

Physics 
Ryan,
First you must change 56 km/h to m/s. In m/s the Initial Velocity is 15.56 m/s. Next use the equation:
S = ViT + (1/2)at^2 and solve for a
21 = (15.56)(2.17) + (1/2)(a)(2.17)^2
a = 5.42 m/s^2
Now that you have the acceleration you can solve for the final velocity using either:
Vf = Vi + at or Vf^2 = Vi^2 + 2as
Vf = 15.56 + (5.42)(2.17) = 3.8 m/s
or
Vf^2 = 15.56^2 + 2(5.42)(21) = 3.8 m/s
As you can see each equation gave the same answer. Overall your answers would be:
a.) 5.42 m/s^2
b.) 3.8 m/s 
Physics 
Nick,
thanks