March 22, 2017

Post a New Question

Posted by on Wednesday, September 2, 2009 at 11:39pm.

I don't know if im doing these problems right, please help...

A car accelerates at a constant rate from zero to 32.6 m/s in 10 seconds and then slows to 14.8 m/s in 5 seconds. What is its average acceleration to the nearest tenth of a m/s2 during the 15 seconds

--would you do 32.6 + 14.8, and then divide by 15?

What was the acceleration during the first 10 seconds in the previous problem

--would you do 32.6 divided be 10?

  • Science- Physics Problem - , Thursday, September 3, 2009 at 12:34am

    Let V1 = starting velocity
    Let V2 = ending velocity

    The problem asks for the average acceleration for the 15 second period. The average acceleration would be the change in velocity over the time period.
    dv/dt = (V2 - V1)/(15 seconds)

  • Science- Physics Problem - , Thursday, September 3, 2009 at 1:24am

    In this case, the starting velocity is zero.

Answer This Question

First Name:
School Subject:

Related Questions

More Related Questions

Post a New Question