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April 18, 2015

April 18, 2015

Posted by **Leslie** on Wednesday, September 2, 2009 at 11:39pm.

A car accelerates at a constant rate from zero to 32.6 m/s in 10 seconds and then slows to 14.8 m/s in 5 seconds. What is its average acceleration to the nearest tenth of a m/s2 during the 15 seconds

--would you do 32.6 + 14.8, and then divide by 15?

What was the acceleration during the first 10 seconds in the previous problem

--would you do 32.6 divided be 10?

- Science- Physics Problem -
**Anonymous**, Thursday, September 3, 2009 at 12:34amLet V1 = starting velocity

Let V2 = ending velocity

The problem asks for the average acceleration for the 15 second period. The average acceleration would be the change in velocity over the time period.

dv/dt = (V2 - V1)/(15 seconds)

- Science- Physics Problem -
**drwls**, Thursday, September 3, 2009 at 1:24amIn this case, the starting velocity is zero.

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