Posted by **Leslie** on Wednesday, September 2, 2009 at 11:39pm.

I dont know if im doing these problems right, please help...

A car accelerates at a constant rate from zero to 32.6 m/s in 10 seconds and then slows to 14.8 m/s in 5 seconds. What is its average acceleration to the nearest tenth of a m/s2 during the 15 seconds

--would you do 32.6 + 14.8, and then divide by 15?

What was the acceleration during the first 10 seconds in the previous problem

--would you do 32.6 divided be 10?

- Science- Physics Problem -
**Anonymous**, Thursday, September 3, 2009 at 12:34am
Let V1 = starting velocity

Let V2 = ending velocity

The problem asks for the average acceleration for the 15 second period. The average acceleration would be the change in velocity over the time period.

dv/dt = (V2 - V1)/(15 seconds)

- Science- Physics Problem -
**drwls**, Thursday, September 3, 2009 at 1:24am
In this case, the starting velocity is zero.

## Answer this Question

## Related Questions

- Physics - Please help! I dont know how to solve these problems! 1 A runner ...
- Physics, Please help!!! - A car accelerates at a constant rate from zero to 32.6...
- Physics - A car accelerates at a constant rate from zero to 36.8 m/s in 10 ...
- physics help! - A car accelerates at a constant rate from zero to 32.6 m/s in 10...
- Physics - A car accelerates at a constant rate from zero to 23.3 m/s in 10 ...
- physics - A car accelerates at a constant rate from zero to 28.7 m/s in 10 ...
- physics - A car accelerates at a constant rate from zero to 20.5 m/s in 10 ...
- Physics - A car accelerates at a constant rate from zero to 25.6 m/s in 10 ...
- Physics - a car accelerates at a constant rate from zero to 26.7 m/s in 10 ...
- physics - A car accelerates at a constant rate from zero to 37.8 m/s in 10 ...

More Related Questions