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Suppose a single electron orbits about a nucleus containing two protons (+2e), as would be the case for a helium atom from which one of the two naturally occurring electrons is removed. The radius of the orbit is 2.65 10-11 m. Determine the magnitude of the electron's centripetal acceleration.

  • physics -

    V^2/R is the centripetal acceleration. You know the value of R. You can get the velocity V by setting the centripetal force equal to the Coulomb force:
    m V^2/R = k Q^2/R^2

    In this case, Q = 2e
    k is the Coulomb constant.
    m is the electron mass and e is its charge.
    You will need to look up these numbers.-

  • physics -

    do it yourself :)

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