Posted by **alice** on Wednesday, September 2, 2009 at 6:29pm.

how do i find the limit of this?

(This symbol:-> is an arrow)

lim of x-> 0 sin^2x/x

can someone please explain?

- math -
**MathMate**, Wednesday, September 2, 2009 at 7:36pm
When an expression involves a division, and the denominator becomes indefinite or zero at the limit, l'Hôpital's rule can be used.

To apply l'Hôpital's rule, take the derivative of the numerator and the denominator, and try to evaluate the expression at the required limit. If the denominator is still indefinite, repeat the procedure.

In the particular case,

Lim x→0 sin²(x)/x

=Lim x→0 2sin(x)cos(x)/1

=2sin(0)cos(0)/1

=2*0*1/1

=0

## Answer this Question

## Related Questions

- calculus - using the squeeze theorem, find the limit as x->0 of x*e^[8sin(1/x...
- Calculus - Find the positive integers k for which lim ->0 sin(sin(x))/x^k ...
- math - can someone please explain this problem? (-> is an arrow) assume that ...
- calculus again - Suppose lim x->0 {g(x)-g(0)} / x = 1. It follows necesarily ...
- Calculus - Find the indicated limits. If the limit does not exist, so state, or ...
- Calculus - Find the indicated limits. If the limit does not exist, so state, or ...
- Calculus - Find the limit. lim 5-x/(x^2-25) x-->5 Here is the work I have so ...
- Math - I'm in Calculus AP and we are learning about limits. I'm having trouble ...
- Calculus - Use the graph to estimate the limit: lim x->0 sin(3x)/x When x is ...
- Limit Calculas - Evaluate lim->4 sin(2y)/tan(5y) Here is what I have so far. ...

More Related Questions