Posted by cara on .
An object dropped from restfrom the top of a tall building falls y=16t^2 feet in the first t seconds.
Find the speed of the object at t=3 seconds and confirmalgebraically. The answer is 96 feet/sec but how do i figure it out? cans omeone show me steps? thanks
The given function is
y(t) = 16 t²
The speed is the derivative of y with respect to t, i.e.
So the speed at t=3 seconds,
To check algebraically, we take the distance travelled at 2.99 and 3.01 seconds, and divide the difference in distance by (3.01-2.99)=0.02 seconds.
= 96 ft/sec. checks with previous calculations
Note: if you have not done calculus before, please let me know.