Posted by **cara** on Wednesday, September 2, 2009 at 2:09pm.

An object dropped from restfrom the top of a tall building falls y=16t^2 feet in the first t seconds.

Find the speed of the object at t=3 seconds and confirmalgebraically. The answer is 96 feet/sec but how do i figure it out? cans omeone show me steps? thanks

- math -
**MathMate**, Wednesday, September 2, 2009 at 2:52pm
The given function is

y(t) = 16 t²

The speed is the derivative of y with respect to t, i.e.

y'(t)=dy/dt=16*(2t)=32t

So the speed at t=3 seconds,

y'(t)=y'(3)=32*3=96 ft/s.

To check algebraically, we take the distance travelled at 2.99 and 3.01 seconds, and divide the difference in distance by (3.01-2.99)=0.02 seconds.

y(2.99)=143.0416 ft

y(3.01)=144.9616 ft

approximate speed

= (y(3.01)-y(2.99))/(3.01-2.99)

= (144.9616-143.0416)/(0.02)

= 96 ft/sec. checks with previous calculations

Note: if you have not done calculus before, please let me know.

## Answer this Question

## Related Questions

- math - You can find the distance d an object falls in feet for time t in seconds...
- math - The approximate distance,S, in feet that an object falls in t seconds ...
- Algebra - the approximate distance, S, in feet that an object falls in t seconds...
- algebra - 5. 16t2 gives the distance in feet a free-falling object falls in t ...
- math - the distance, d, an object falls when dropped from a tower varies ...
- College Algebre - Here is the math problem: The height of an object in free fall...
- Calculus - A rock is dropped from the top of a 400-foot-tall building. Its ...
- Math - An object is thrown from the top of an 80 foot building with an initial ...
- math - The approximate distance, s, in feet that an object falls in t seconds ...
- MATH - The function s(t) = 16t^2 models the distance, s(t), in feet, that an ...

More Related Questions