Posted by **Anonymous** on Wednesday, September 2, 2009 at 1:54pm.

I have a square that is divided into 2 triangles. In the middle of the top triangle there is this: 62 in. and at the bottom corner of the same triangle it says 45 degrees. Could some explain to me how to find the area and the perimeter? I'm not sure what I'm supposed to do with the radical.

- MATH -
**MathMate**, Wednesday, September 2, 2009 at 2:00pm
So the square has a diagonal whose length is 6√2 in. The angle made by the diagonals with the sides of a square is always 45° as stated.

If the side length of a square is x, then the length of the diagonal is x√2, which implies that the given square is of side length 6 inches.

Would you now be able to proceed to find the area and perimeter of a square of side length 6 inches?

- MATH -
**Anonymous**, Wednesday, September 2, 2009 at 7:02pm
Got it! Thanks so much!

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