Posted by Michelle on Tuesday, September 1, 2009 at 6:43am.
What is the molarity of a solution in which 13.7 g of calcium chloride is dissolved in water to a final volume of 750.0 mL?
Chemistry II - MathMate, Tuesday, September 1, 2009 at 8:12am
Atomic weight of
Ca : 40
Cl : 35.5
Molecular weight of CaCl2=40+35.5*2=111
Moles=weight in grams/Molecular weight
=13.7/111 = 0.1234 moles
Molarity = 0.1234 moles/750 ml.
Please check the atomic weights and the calculations.
Chemistry II - Dr Russ, Tuesday, September 1, 2009 at 8:22am
Also note that units are missing and incorrect in places so that equations do not balance.
Relative Atomic Mass (RAM) of
Ca : 40
Cl : 35.5
Relative Molecular Mass of CaCl2=40+(35.5*2)=111
Moles=mass in grams/RAM
=13.7 g/111 g mol^-1
= 0.1234 mol
Molarity of solution = 0.1234 mol/0.7500 l.
or 0.165 M
Chemistry II - MathMate, Tuesday, September 1, 2009 at 10:03am
Thank you Dr. Russ.
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