Posted by ROSEL on Monday, August 31, 2009 at 10:14pm.
I would write this as
(CH3)2CH=CH(CH3)2
A chemist is producing copper(II) chloride using the following reaction:
Cu(s) + Cl2(g) --> CuCl2(s)
In one reaction, the chemist uses 15.0 g of copper metal and 10.0 g of chlorine gas as reactants. When the reaction reaches completion, 16.0 g of copper(II) chloride has been produced. What was the percent yield of the reaction?
You don't stand much chance of an answer when you piggy back onto another question. You should go to the top of the page, click on Post a new question, and post the new question.
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