The concept i get, but somehow i just can't execute this problem, please help me!
You are given vectors A = 5.5 6.2 and B = - 3.7 7.4 . A third vector C lies in the xy-plane. Vector C is perpendicular to vector A and the scalar product of C with B is 19.0.
I need x and y components for vector C
physics [vectors] - Damon, Monday, August 31, 2009 at 6:09am
A = 5.5 i + 6.2 j
B = -3.7i + 7.4 j
C = x i + y j
A dot C = |A| |C| cos theta
if perpendicular theta is 90 degrees and cos theta = 0
5.5 x + 6.2 y = 0
B dot C = 19
-3.7 x + 7.4 y = 19.0
solve those two equations for x and y
physics [vectors] - DN, Tuesday, November 17, 2015 at 12:28pm