Thursday

April 17, 2014

April 17, 2014

Posted by **anonymous** on Saturday, August 29, 2009 at 2:48pm.

a. m/s^2

b. m

c. s

d. m^2

2. If a is acceleration (m/s^2), delta(v) is change in velocity (m/s), delta(x) is change in position (m), and delta(t) is the time interval (s), which equation is NOT dimensionally correct?

a. delta(t) = delta(x)/v

b. a = v^2/delta(x)

c. delta(v)=a/delta(t)

d. delta(t)^2=2delta(x)/a

---

With number 1, I'm just not really sure. I think the unit for delta(x) is throwing me off a little.

For number 2, I know what it's asking, but I'm not too good at finding dimensionally correct equations. I'm leaning toward d, however. I don't see time getting squared. A little help, please?

Thanks!

- Physics -
**bobpursley**, Saturday, August 29, 2009 at 3:16pmon the first deltax has units of meters.

on the second. Put the dang units for each in, and just reduce to see if it matches.

For instance:

a. s=m/(m/s)= s

duh, those match.

now do the rest

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