Sunday

December 21, 2014

December 21, 2014

Posted by **j** on Friday, August 28, 2009 at 6:38pm.

- math -
**Reiny**, Friday, August 28, 2009 at 6:57pmLet the time between train B passing the station and catching up to train A be t hours

so time for train A from station to catchup place is t + 1/2 hours

so I see this equation:

64t = 60(t+1/2)

which solves to t = 7.5

so the time when train B catches up to train A is 3:15 PM

(7:45 + 7:30 = 15:15 = 3:15 pm)

- math -
**Nathan**, Thursday, September 3, 2009 at 2:19amThe previous answer is wrong. The correct answer is 1:45pm (time to catch up is 6 hours).

**Answer this Question**

**Related Questions**

algebra - Train A and B are traveling in the same direction on parallel tracks. ...

Algebra - Trains A and B are traveling in the same direction on parallel tracks...

Algebra Help PLZ - I have tried this several different ways and I am just not ...

math/algebra - Trains A and B are traveling in the same direction on parallel ...

math algebra - Trains A and B are traveling the same direction on parallel ...

math - Trains A and B are traveling in the same direction on parrallel tracks. ...

math - Trains A and B are traveling in the same direction on parallel tracks. ...

algebra - Trains A and B are traveling in the same direction on parrallel tracks...

algebra - Train A and B are traveling in the same direction on parallel tracks. ...

algebra - Train A and B are traveling in the same direction on parallel tracks. ...