Posted by **j** on Friday, August 28, 2009 at 6:38pm.

Train A and B are traveling in the same direction on parallel tracks. Train A is traveling at 60 mph and Train B is traveling 64 mph. Train A passes a station at 7:15 AM. If Train B passes the same station at 7:45 AM, at what time will Train B catch up to Train A?

- math -
**Reiny**, Friday, August 28, 2009 at 6:57pm
Let the time between train B passing the station and catching up to train A be t hours

so time for train A from station to catchup place is t + 1/2 hours

so I see this equation:

64t = 60(t+1/2)

which solves to t = 7.5

so the time when train B catches up to train A is 3:15 PM

(7:45 + 7:30 = 15:15 = 3:15 pm)

- math -
**Nathan**, Thursday, September 3, 2009 at 2:19am
The previous answer is wrong. The correct answer is 1:45pm (time to catch up is 6 hours).

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