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Posted by on Friday, August 28, 2009 at 4:19pm.

What was the percent increase in the population in S.America from 1900 to 2000?

1900 = 38,000,000
1950 = 111,000,000
2000 = 515,000,000

Can someone please help guide me?? I am not great at percentages.. would I add the three and then divide by 3?

  • Math - , Friday, August 28, 2009 at 4:25pm

    According to your problem, you don't need to do anything with the numbers for 1950.

    First:

    515,000,000 - 38,000,000 = 477,000,000

    Next:

    38,000,000 / 477,000,000 = ?

    Multiply your answer by 100 (or move the decimal point two places to the right) to find the percent increase.

  • Math - , Friday, August 28, 2009 at 4:28pm

    Thank you Ms. Sue

    the answer I got from your help was: 85%

  • Math - , Friday, August 28, 2009 at 4:57pm

    85% does not look right.

    Percentage increases are calculated as
    (new value-old value) / old value.

    If the population of Tokyo went from 10.18 millions to 12.79 millions in 2007, the percentage increase would be:
    (12.79-10.18)/10.18
    =0.2564
    =25.64%

    As suggested by Ms Sue, do not take into account of the 1950 numbers.
    So percentage increase is from 38 millions in 1900 to 515 millions in 2000, or
    (515-38)/38
    =12.55
    =1255%

    You can check the data provided at the following link:
    http://www.hist.umn.edu/~rmccaa/lademotr/sld003.htm

  • Math - , Friday, August 28, 2009 at 5:02pm

    hmmm confused now

  • Math - , Friday, August 28, 2009 at 5:09pm

    I'm sorry, but I misstated the division problem.

    As MathMate pointed out, it should be:

    477,000,000 / 38,000,000 = 12.55 = 1255%

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