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July 22, 2014

July 22, 2014

Posted by **Tifna** on Friday, August 28, 2009 at 3:24am.

Could someone please help me with this question? Thanks alot

- AP physics -
**bobpursley**, Friday, August 28, 2009 at 9:37amHow much energy does it take to go 1.5m?

mgh=m*9.8*1.5= 14.7m joules

How much KE does the fish have initially?

1/2 m v^2= 1/2 m (6.26^2)=19.6m

Well, there is plenty of energy to go that high. So, will the fish go that high and still land 1m kupstream?

At the top , vvertical is zero. So how long will the fish take to fall that same distance?

vvertical= vverticalinitial-gt

0=6.26sinTheta-gt

This is the same time it takes to get to the top, so

t= 6.26sinTheta/g

How far does the fish travel hoizontally in that time?

1=6.26cosTheta*t

= 6.26costheta*6.26sinTheta/g

solvefor theta. Remember 2cosAsinA=sin2A

If you get an angle, the fish can do it.

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