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December 19, 2014

December 19, 2014

Posted by **RAYMOND** on Thursday, August 27, 2009 at 8:44pm.

- CACULUS -
**Reiny**, Thursday, August 27, 2009 at 10:01pm(cosx)^2 = 2sinxcox

(cosx)^2 - 2sinxcosx = 0

cosx(cosx - 2sinx) = 0

cosx = 0 or cosx = 2sinx

if cosx=0 then**x = pi/2**

if cosx = 2sinx

sinx/cosx = 1/2

tanx = 1/2**x = .46365**

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