The sum of my three digit date is 11. My hundreds and tens digits could be the sides of a square with an area of 25 and a perimeter of 20. What year am I?
20 / 4 = 5
square root of 25 = 5
55_
What number goes in the ones place?
Thanks..I couldn't figure it out
To find the year, we need to identify the three-digit number where the sum of the digits is 11 and the hundreds and tens digits form a square with an area of 25 and a perimeter of 20.
Let's start by determining the possible values for the hundreds and tens digits. For a square's area to be 25, the sides must be 5 units each (since 5 * 5 = 25). Additionally, for a square's perimeter to be 20, it must have four sides of length 5 (since 5 + 5 + 5 + 5 = 20). Therefore, the hundreds and tens digits can only be 5 and 5.
Now, we know that the sum of the digits of the three-digit number is 11. If the hundreds and tens digits are both 5, the units digit must be 1 (since 5 + 5 + 1 = 11). So, the three-digit number is 551, which corresponds to the year 551.
Therefore, the year you are referring to is 551.