Posted by Kyra on Thursday, August 27, 2009 at 2:22pm.
write your type of questions this way :
(v2-4v-21)/(3v2+6v)(v2+8v)/(v2+11+24)
= (v-7)(v+3)/[3v(v+2)](v)(v+8)/[(v+3)(v+8)]
= (v-7)/[v(v+2)]
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