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April 21, 2014

April 21, 2014

Posted by **Kyra** on Thursday, August 27, 2009 at 2:22pm.

- Math -
**Reiny**, Thursday, August 27, 2009 at 3:02pmwrite your type of questions this way :

(v2-4v-21)/(3v2+6v)(v2+8v)/(v2+11+24)

= (v-7)(v+3)/[3v(v+2)](v)(v+8)/[(v+3)(v+8)]

= (v-7)/[v(v+2)]

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