math
posted by Anonymous on .
where is the vertex of the graph of y=x2+6x2?

complete the square:
y=x2+6x2
= x^2 + 6x + 9  9 2
= (x+3)^2  11
so the vertex is (3,11)
or
for y = ax^2 + bx + c, the x value of the vertex is b/(2a)
sub that back in the original equation to get the y of the vertex.
x of vertex = 6/2 = 3
y = (3)^2 + 6(3)  2 = 11