Posted by **Anonymous** on Thursday, August 27, 2009 at 11:40am.

where is the vertex of the graph of y=x2+6x-2?

- math -
**Reiny**, Thursday, August 27, 2009 at 12:08pm
complete the square:

y=x2+6x-2

= x^2 + 6x **+ 9 - 9 **-2

= (x+3)^2 - 11

so the vertex is (-3,-11)

or

for y = ax^2 + bx + c, the x value of the vertex is -b/(2a)

sub that back in the original equation to get the y of the vertex.

x of vertex = -6/2 = -3

y = (-3)^2 + 6(-3) - 2 = -11

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