suppose that A=D+E and that D/A= 0.35 solve for A/E.
sorry I still don't understand
substitute in what you can from the info you are given
in this case change 'A' to 'D+E'
this gives us D/D+E =0.35 & D+E/E
see if you can take it from here
or in
A=D+E , divide each term by A
A/A = D/A + E/A
1 = .35 + E/A
.65 = E/A
E/A = 65/100 = 13/20
Then A/E = 20/13
ok so this would = 1.54
just too see if i got it suppose A=D=E D/A=0.75 would D/E= .25
To solve for A/E, we can start by rearranging the equation A = D + E to isolate E on one side of the equation.
Step 1: Start with the equation A = D + E
Step 2: Subtract D from both sides of the equation to get A - D = E
Now that we have E isolated, we can substitute the given value of D/A into the equation and solve for A/E.
Step 3: Substitute D/A = 0.35 into the equation to get A - D = E
Step 4: Multiply both sides of the equation by A to get A(A - D) = AE
Now we need to solve for A/E.
Step 5: Substitute the equation A = D + E into A(A - D) = AE to get (D + E)(A - D) = AE
Step 6: Expand the equation to get (DA - D^2) + (EA - ED) = AE
Step 7: Rearrange the equation to group terms with similar variables together, which gives DA + EA - D^2 - ED = AE
Step 8: Subtract AE from both sides of the equation to get DA + EA - D^2 - ED - AE = 0
Step 9: Combine like terms to get DA + EA - AE - D^2 - ED = 0
Step 10: Factor out common terms to get A(D + E - E) - D(D + E) = 0
Step 11: Simplify the equation to get AD - D(D + E) = 0
Step 12: Expand the equation to get AD - D^2 - DE = 0
Step 13: Rearrange the equation to get AD - DE = D^2
Now that we have AD - DE = D^2, we can solve for A/E by dividing both sides of the equation by DE.
Step 14: Divide both sides of the equation by DE to get (AD - DE)/DE = D^2/DE
Step 15: Simplify the equation to get A/E - 1 = D/DE
Step 16: Multiply both sides of the equation by E to isolate A/E, which gives A/E - 1 = D/E
Step 17: Add 1 to both sides of the equation to get A/E = D/E + 1
Therefore, the solution to A/E is D/E + 1. You can substitute the given value of D/A into the equation to get the numerical value.