Posted by marie on Wednesday, August 26, 2009 at 7:27pm.
This problem fits a binomial proportion 2-sample z-test using proportions.
Hypotheses:
Ho: p1 = p2
Ha: p1 < p2 -->one-tailed test (shows a specific direction)
The formula is:
z = (p1 - p2)/√[pq(1/n1 + 1/n2)]
...where 'n' = sample sizes, 'p' is (x1 + x2)/(n1 + n2), and 'q' is 1-p.
I'll get you started:
p = (42 + 62)/(200 + 200) = ? -->once you have the fraction, convert to a decimal (decimals are easier to use in the formula)
q = 1 - p
p1 = 42/200
p2 = 62/200
Convert all fractions to decimals. Plug those decimal values into the formula and find z. Once you have this value, you will be able to determine the p-value or the actual level of this test statistic by using a z-table. Determine the outcome of the test (whether or not to reject the null). Draw your conclusions from there.
I hope this will help get you started.
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