Posted by John on Tuesday, August 25, 2009 at 11:02pm.
To work as a solvent pair, the two solvents must be miscible with each other. Therefore, e would not be a good pair. I will leave the others to you.
E would not be a good pair because one is polar and the other is nonpolar
So for B because they are both nonpolar would they be miscible?
Not necessarily. The polar/non-polar point makes them immiscible. B is miscible since both are non-polar.
Ah I see, so the rest A-D are all miscible since A, C, and D are both polar while B are both non-polar.
Yes, e is the only pair not miscible. One point I should make is that just because they are miscible doesn't make them a good pair for some recrystallizations. Some recrystallizations must be determined by experiment to see if there is a single solvent or a solvent pair that may work. Here is a site where that is amplified somewhat.
http://www.hartnell.edu/faculty/shovde/chem12a/lablecturehandouts/recrystallizationlecture.htm
An additional point is that a mixture of a pair of solvents that are too close in polarity may not be any better than a single solvent.
Another consideration on a larger scale where you will want to recover the solvent which is that this is much easier to do if a single solvent is used, or a pair that are easily separated.
Thank you very much for the responses. It has helped me alot!
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