A player uses a hockey stick to increase the speed of a 0.200 kg hockey puck by 6 m/s in 2 seconds. how 1. much did the hockey puck accelerat?

2. how much force was exerted on the puck?

a=(v-u)/t

where v=final velocity, u=initial velocity and t= time in seconds

initial is 0 m/s

go from here yourself :)

ok now Force

Force = mass*acceleration

use the acceleration you calculated in the first question to find the force exerted on the puck

To calculate the acceleration of the hockey puck, you can use the formula:

acceleration = change in velocity / time

Given that the change in velocity is 6 m/s and the time is 2 seconds, we can substitute these values into the formula:

acceleration = 6 m/s / 2 s
acceleration = 3 m/s²

Therefore, the hockey puck experienced an acceleration of 3 m/s².

To calculate the force exerted on the puck, you can use Newton's second law of motion:

force = mass × acceleration

Given that the mass of the hockey puck is 0.200 kg and the acceleration is 3 m/s², we can substitute these values into the formula:

force = 0.200 kg × 3 m/s²
force = 0.6 N

Therefore, the force exerted on the puck is 0.6 Newtons.