Two tuning forks are struck at the some time. One tuning fork has a requency of 20 Hz while the second tuning fork has a frequency of 226 Hz. How many beats will result?

They add and subtract.

20 + 226 = 246
226-20 = 205
Most human ears can hear both 246 and 206.

To find out how many beats will result when two tuning forks with different frequencies are struck at the same time, we need to calculate the difference in frequency between the two tuning forks.

The formula to calculate the number of beats is:

Number of beats = |(Frequency of Tuning Fork 1) - (Frequency of Tuning Fork 2)|

In this case, the frequency of Tuning Fork 1 is 20 Hz, and the frequency of Tuning Fork 2 is 226 Hz. Plugging the values into the formula, we get:

Number of beats = |20 Hz - 226 Hz|

Taking the absolute value of the difference, we have:

Number of beats = | -206 Hz |

Now, we can calculate the answer:

Number of beats = 206 Hz

Therefore, when these two tuning forks are struck at the same time, 206 beats will result.