Posted by **Chrissy** on Monday, August 24, 2009 at 8:11pm.

Could someone please explain how to figure this out step by step. I'll give you one of my problems and I'll try to figure out the rest.

Directions: For each situation find the value of x and the measure of the indicated segment.

1. UY=4x-3, YV=x; UV

- Geometry Question plz help -
**bobpursley**, Monday, August 24, 2009 at 8:13pm
If UY and YV are segments of a straight line, then

UY+YV=UV

4x-3+x=UV

If one knows UV, then one can solve for x.

- Geometry Question plz help -
**Chrissy**, Monday, August 24, 2009 at 8:16pm
Do I add 4x+x which equals 5x so would it be 5x-3=UV??

- Bobpursley plz help -
**Chrissy**, Monday, August 24, 2009 at 8:20pm
could you check the one i did myself

2. UV=x+6,UY=x-1;YV

UY+UY=YV

x+6-1=YV

Answer: x-5=YV

- Geometry Question plz help -
**bobpursley**, Monday, August 24, 2009 at 8:32pm
well, since UV is greater then UY, it means that UV is the longer segment, UY one part of it, and YV the other part.

So UY+YV=UV

then proceed.

- RE: TO Bobpursley -
**Chrissy**, Monday, August 24, 2009 at 8:36pm
So would the answer be x^2+YV=7

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