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March 30, 2017

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A circular steel wire 2.00 m is to stretch no more than 0.25 cm when a tensile force of 400 N is applied to each end of wire. What minimum diameter is required for the wire?

  • physics - ,

    area = pi d^2/4
    length = 2 m
    change in length = .0025 m

    change in length/length = .0025/2

    = tensile stress/E = 400/(pi d^2/4 E)
    so
    .00125 = 400/ (pi d^2/4 E)

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