Question

please help emergency.

find double integral of x times y time e to the <x plus y> . bounded from <0,1> x <0,1>

Answer 1

∫xe^xdx

= (x-1)e^x
Evaluation from 0 to 1 gives [0-(-1)]=1

Since x and y are two independent variables,
∫∫xye^x+ydxdy
∫∫xe^x ye^ydxdy
=∫xe^xdx ∫ye^ydy
=1*1
=1