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August 29, 2014

Homework Help: Physics (Algebra Bit)

Posted by QUESTION on Thursday, August 20, 2009 at 8:43pm.

I still need help on my other question as well...

A runner hopes to complete the 10,000 m run in less than 30.0 min. AFter running at constant speed exactly 27.0 min there are still 1100 m to go. The runner must then accelerate at .20 s^-2 m for how many seconds in order to achieve the desired time?

ok well I foudn if you consider the first part of the run to have zero acceleration then you get 5.494 s^-1 m for the initial velocity for the second part of the race before the acceleration occurs...

so I'm trying to solve for t for the second part

reorginizing this equation

X = Xo + Vo t + 2^-1 a t^2

has more than one t in it and can't be taken out because there is a Vo and a acceleration

my only other choice is

a = t^-1 (V - Vo)

the final velocity can be assumed to be zero which it wouldn't be because most people would continue to run after the finish line but even if you did assume it to be zero then when you rearanged for time

t = a^-1 - Vo

I get a negative time...

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