Posted by natalin on Tuesday, August 18, 2009 at 8:15pm.
Given:
K(0,0), L(18,0), M(6,12)
To find:
Equations of sides of triangle KLM.
Equations of altitudes of the triangle, namely KK1, LL1, MM1, where K1, L1 and M1 are the intersection of the altitudes of the points K,L,M and the opposite side.
Prove that the three altitudes meet at a single point at the orthocentre.
Equation of a line passing through one point A and perpendicular to a line passing through points B and C is:
(y-ya)(xc-xb)+(x-xa)(yc-yb)=0
Substituting in turn points K, L and M for A,B and C, the equations of the altitudes are:
KK1 : y=x
LL1 : y=9-x/2
MM1 : x=6
The line MM1 is a line parallel to the y-Axis.
Substitute x=6 into the other equations, we get, for the intersection point:
with LL1: y=9-6/2=6, thus (6,6)
with KK1: y=x, thus (6,6)
Therefore the orthocentre is at (6,6).