physics parallel plate
posted by Anonymous on .
A proton traveling at a speed 1.0*106 m/s of enters the gap between the plates of a 2.0cmwide parallelplate capacitor. The surface charge densities on the plates are 1*10^6 C/m2.
How far has the proton been deflected when it reaches the far edge of the capacitor? Assume the electric field is uniform inside the capacitor and zero outside.
I know the formula is E=symbol eta/epsilon for a parallel plate. But I don't what to do or how to start this.

Knowing E, you then know the force on the proton. From the velocity, you know the time the proton is in the plates (2cm wide).
F*time=massproton*velocity change.
the original velocity in the direction of E is zero, so velcity change must be final velocity, or twice average velocity during the transit.
distancedeflected=avgvelocity*time
=velocitychange/2 * time
you take it from here.