Posted by Anonymous on Monday, August 17, 2009 at 7:33pm.
A proton traveling at a speed 1.0*106 m/s of enters the gap between the plates of a 2.0cmwide parallelplate capacitor. The surface charge densities on the plates are 1*10^6 C/m2.
How far has the proton been deflected when it reaches the far edge of the capacitor? Assume the electric field is uniform inside the capacitor and zero outside.
I know the formula is E=symbol eta/epsilon for a parallel plate. But I don't what to do or how to start this.

physics parallel plate  bobpursley, Monday, August 17, 2009 at 7:37pm
Knowing E, you then know the force on the proton. From the velocity, you know the time the proton is in the plates (2cm wide).
F*time=massproton*velocity change.
the original velocity in the direction of E is zero, so velcity change must be final velocity, or twice average velocity during the transit.
distancedeflected=avgvelocity*time
=velocitychange/2 * time
you take it from here.
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