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April 18, 2014

April 18, 2014

Posted by **matrix school 2** on Friday, August 14, 2009 at 4:21pm.

- Differential Calculus -
**Damon**, Friday, August 14, 2009 at 5:38pmwhen q = 3, p = (2*9-5)^2 =169

dp/dq = 2 (2q^2-5)(4q)

when q = 3, dp/dq = 312

dq = .007*3 = .021

so dp = 312*.021 = 6.552

100 * dp/p = 100 *6.552/169 = 3.88 %

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