Posted by MaryK on Friday, August 14, 2009 at 3:35pm.
Does v = 1/(2t+6) or or 1/(2t) + 6 or t/2 +6 ?
Whichever it is, plug in 6 for t and compute the resulting v.
This is what I am not grasping computing the formulas...
this formula is
v=1/2"fraction"t+6 with the given t-value, 6?
To plug in 6 for t, replace t in the equation with 6.
For example, given the equation y = x^2+x+5, to find y at x = 1, replace x in the equation with 1.
y = x^2 + x + 5 at x=1
y = 1^2 + 1 + 5
See how x is replaced by 1 in the equation?
So for v = (1/2)t + 6, how do you think you can find v at a t value of 6?
v=1/2(6)+6
1/2*6/1 = 6/2 with 2going into 6 - four times plus 6 equals 10? I have a feeling this is the not the correct way to solve for the equation given I replace the t with 6? Correct?
v=(1/2)(6)+6
That is correct. However, you seem to have calculated incorrectly. (1/2)*6 is 3, not 4.
v = 3+6
v = 9
I knew it!...this is my problem how did you calculate (1/2)*6 is 3...this is frustrating me..in getting the correct answers...I do not get it and I am a full blown adult - sorry :(
(1/2)*6 is the same as 6/2
6 = 2*3, so 6/2 = (2*3)/2. 2 cancels out, leaving you with 3.
ty