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November 28, 2015
Posted by **matrix school 2** on Friday, August 14, 2009 at 2:59pm.

q=3, dq=.007*3

Now solve for dp and solve for P at q=3

percentage change in p then is dp/p divided by 100.

alright...

dp(2q^2-5)^2, dp/dq = 2(2q^2-5)

dp = 0.007x3 = 0.021

dp = (2(2(2)^2-5)^2 = (6)^2 = 36

36x0.021 = 0.756

(2(2)^2-5)^2 (3)^2 = 9

0.021/9 x 100 = 2.3%

pls correct me.

- Differential Calculus -
**Damon**, Friday, August 14, 2009 at 5:44pmdp/dq = 2(2q^2-5)

no

if p = (2q^2-5)^2

then dp/dq = 1 (2q^2-5)^1 (4q)

because

d/dq (2q^2) = 4 q