Posted by **matrix school 2** on Friday, August 14, 2009 at 2:15pm.

Given that p=(2q^2-5)^2. when q=3, it is increased by 0.7%. find the appropriate percentage in p.

solution

dp = 2(2q^2-5) (2dq)

dp = (4x(18-5)(0.7%)

dp = 4(13)(0.7%)

am lost from here

is dp=52x0.7/100= 0.364%

Responses

Differential Calculus - bobpursley, Friday, August 14, 2009 at 1:52pm

p=(2q^2-5)^2

dp=2(2q^2-5)(4q)dq

ok from here

dp= -8

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