Differential Calculus
posted by matrix school 2 .
Given that p=(2q^25)^2. when q=3, it is increased by 0.7%. find the appropriate percentage in p.
solution
dp = 2(2q^25) (2dq)
dp = (4x(185)(0.7%)
dp = 4(13)(0.7%)
am lost from here
is dp=52x0.7/100= 0.364%
Responses
Differential Calculus  bobpursley, Friday, August 14, 2009 at 1:52pm
p=(2q^25)^2
dp=2(2q^25)(4q)dq
ok from here
dp= 8

you have the expression for dp.
q=3, dq=.007*3
Now solve for dp and solve for P at q=3
percentage change in p then is dp/p divided by 100. 
y^4=c(x^2+4y^2)

y^4=c(x^2+4y^2)