Differential Calculus
posted by matrix school 2 on .
Given that p=(2q^25)^2. when q=3, it is increased by 0.7%. find the appropriate percentage in p.
solution
dp = 2(2q^25) (2dq)
dp = (4x(185)(0.7%)
dp = 4(13)(0.7%)
am lost from here
is dp=52x0.7/100= 0.364%

p=(2q^25)^2
dp=2(2q^25)(4q)dq
check that.