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January 30, 2015

January 30, 2015

Posted by **matrix school 2** on Friday, August 14, 2009 at 1:19pm.

solution

dp = 2(2q^2-5) (2dq)

dp = (4x(18-5)(0.7%)

dp = 4(13)(0.7%)

am lost from here

is dp=52x0.7/100= 0.364%

- Differential Calculus -
**bobpursley**, Friday, August 14, 2009 at 1:52pmp=(2q^2-5)^2

dp=2(2q^2-5)(4q)dq

check that.

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