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April 1, 2015

April 1, 2015

Posted by **B.B.** on Thursday, August 13, 2009 at 12:02pm.

Consider the experiment of drawing two cards without replacement from an ordinary deck of playing cards. What are the odds in favor of drawing a spade or a heart?

Answer: P(Spade)*P(Spade)=(13/52)x(13/51)=169/2652=0.06372. Is this right?

Thanks.

- Math -
**bobpursley**, Thursday, August 13, 2009 at 4:59pmNo, you did the probability of drawing two spades. As I read the question, you want the probabilitiy of one spade or one heart,

Pr= Pr(one spade and one club/diamond)+pr(heart and one club/diamond).

Pr=13/52* 26/51 + 13/52*26/51

check my thinking.

- Math -
**B.B.**, Friday, August 14, 2009 at 9:29amSo, do I multiply 13/52*26/51 for both and then add?

Ex: 13/52*26/51+13/52*26/51=

338/2652+338/2652=

676/2652

Is this right?

Thanks.

- Math -
**B.B**, Friday, August 14, 2009 at 3:20pmDid I do the problem right? Was the answer 676/2652?

Thanks.

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