Posted by **B.B.** on Thursday, August 13, 2009 at 12:02pm.

Did I do this problem right?

Consider the experiment of drawing two cards without replacement from an ordinary deck of playing cards. What are the odds in favor of drawing a spade or a heart?

Answer: P(Spade)*P(Spade)=(13/52)x(13/51)=169/2652=0.06372. Is this right?

Thanks.

- Math -
**bobpursley**, Thursday, August 13, 2009 at 4:59pm
No, you did the probability of drawing two spades. As I read the question, you want the probabilitiy of one spade or one heart,

Pr= Pr(one spade and one club/diamond)+pr(heart and one club/diamond).

Pr=13/52* 26/51 + 13/52*26/51

check my thinking.

- Math -
**B.B.**, Friday, August 14, 2009 at 9:29am
So, do I multiply 13/52*26/51 for both and then add?

Ex: 13/52*26/51+13/52*26/51=

338/2652+338/2652=

676/2652

Is this right?

Thanks.

- Math -
**B.B**, Friday, August 14, 2009 at 3:20pm
Did I do the problem right? Was the answer 676/2652?

Thanks.

## Answer This Question

## Related Questions

- Math - I was wondering if someone could help me check my work on this problem ...
- math - Consider the experiment of drawing two cards without replacement from an ...
- Math 157 - What are the odds in favor of drawing a spade and a heart without ...
- MATH Prob. - What are the odds in favor of drawing a spade and a heart if ...
- Math - Two cards are drawn without replacement from an ordinary deck of 52 ...
- math - Two cards are drawn without replacement from an ordinary deck of 52 ...
- stat - Drawing a spade form a regular deck of playing cards and then drawing ...
- Math check answer - Two cards are drawn without replacement from an ordinary ...
- Math check answer - Two cards are drawn without replacement from an ordinary ...
- Math check answer - Two cards are drawn without replacement from an ordinary ...

More Related Questions