Posted by tiara on Tuesday, August 11, 2009 at 9:13pm.
value=3x^2-2y^2 - 2x^2+3y
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3^2-2*5^2+3(5)
Given
f(x,y) = ((3x)²-(2y)²) - ((2x)²-3y)
Find f(3,5).
f(3,5)
=((3*3)²-(2*5)²)-((2*3)²-3*5)
=(9²-10²)-(6²-15)
=(81-100)-(36-15)
=-19-21
=-40
Please check if the interpretation of the question is correct.
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