algebra
posted by tiara on .
when x=3 and y=5 how much does the value of 3x to the seond power minus 2y to the second power exceed the value of 2x to the second power minus 3y

value=3x^22y^2  2x^2+3y
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3^22*5^2+3(5) 
Given
f(x,y) = ((3x)²(2y)²)  ((2x)²3y)
Find f(3,5).
f(3,5)
=((3*3)²(2*5)²)((2*3)²3*5)
=(9²10²)(6²15)
=(81100)(3615)
=1921
=40
Please check if the interpretation of the question is correct.