Posted by Anonymous on .
The number of accidents that occur at the intersection
of Pine and Linden streets between 3 p.m. and
6 p.m. on Friday afternoons is 0, 1, 2, or 3, with probabilities
of 0.84, 0.13, 0.02, and 0.01, respectively.
Graph this probability distribution. What is the
expected value for the random variable given the
number of accidents?
The expected value of the random accidents can be found by the summation of the number of accidents * their probabilities.
E(x) = 0*0.84 + 1*0.13 + 2*0.02 + 3*0.01