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July 29, 2014

July 29, 2014

Posted by **B.B.** on Monday, August 10, 2009 at 9:27am.

Answer: 1/2

Is this correct?

Could you please explain if I got it wrong?

Thanks.

- Math -
**bobpursley**, Monday, August 10, 2009 at 10:01amNo. Figure the probability of getting three

**tails**in three tosses, then the probability of getting at least one head is that subtracted from one.

Pr(atleastoneHead)=1-Pr(three tails)

- Math -
**Reiny**, Monday, August 10, 2009 at 10:03amThe sample space of outcomes is small enough so we can list them

HHH

HHT

HTH

HTT

THH

THT

TTH

TTT

notice that there are 7 with at least one H, and only one with no H

so the odds in favour of getting at least one head in three successive flips of a coin is 7:1

(I hope you meant "odds" and not probability.

The prob of at least one head is 7/8

odds in favour of some some event = (prob of that event):(prob of NOT that event)

- Math -
**B.B.**, Monday, August 10, 2009 at 10:08amThanks.

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