Posted by **B.B.** on Monday, August 10, 2009 at 9:27am.

What are the odds in favor of getting at least one head in three successive flips of a coin?

Answer: 1/2

Is this correct?

Could you please explain if I got it wrong?

Thanks.

- Math -
**bobpursley**, Monday, August 10, 2009 at 10:01am
No. Figure the probability of getting three **tails** in three tosses, then the probability of getting at least one head is that subtracted from one.

Pr(atleastoneHead)=1-Pr(three tails)

- Math -
**Reiny**, Monday, August 10, 2009 at 10:03am
The sample space of outcomes is small enough so we can list them

HHH

HHT

HTH

HTT

THH

THT

TTH

TTT

notice that there are 7 with at least one H, and only one with no H

so the odds in favour of getting at least one head in three successive flips of a coin is 7:1

(I hope you meant "odds" and not probability.

The prob of at least one head is 7/8

odds in favour of some some event = (prob of that event):(prob of NOT that event)

- Math -
**B.B.**, Monday, August 10, 2009 at 10:08am
Thanks.

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