Posted by B.B. on Monday, August 10, 2009 at 9:27am.
What are the odds in favor of getting at least one head in three successive flips of a coin?
Answer: 1/2
Is this correct?
Could you please explain if I got it wrong?
Thanks.

Math  bobpursley, Monday, August 10, 2009 at 10:01am
No. Figure the probability of getting three tails in three tosses, then the probability of getting at least one head is that subtracted from one.
Pr(atleastoneHead)=1Pr(three tails)

Math  Reiny, Monday, August 10, 2009 at 10:03am
The sample space of outcomes is small enough so we can list them
HHH
HHT
HTH
HTT
THH
THT
TTH
TTT
notice that there are 7 with at least one H, and only one with no H
so the odds in favour of getting at least one head in three successive flips of a coin is 7:1
(I hope you meant "odds" and not probability.
The prob of at least one head is 7/8
odds in favour of some some event = (prob of that event):(prob of NOT that event)

Math  B.B., Monday, August 10, 2009 at 10:08am
Thanks.
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