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November 26, 2014

Homework Help: General Chem

Posted by Hina on Sunday, August 9, 2009 at 10:02pm.

A weak acid has Ka= 1*10^-3. If [HA]= 1.00 M what must be [A-] for the pH to be pH 2.7?

My work:
pH= Pka + log(B/A)
2.7= 3 + log (B/A)

Kw= Ka* Kb
1*10^-14= 1*10^-3 * Kb
Kb= 1*10^-11

I don't know how to go about from here

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