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March 4, 2015

March 4, 2015

Posted by **Laritza** on Sunday, August 9, 2009 at 5:59pm.

For the following data from independent samples, could the null hypothesis that the population means are equal be rejected at the 0.05 level?

Sample1 Sample2 Sample3 Sample4

15.2 10.2 14.9 11.5

12.2 12.1 13.0 13.1

15.0 8.5 10.8 11.5

14.6 8.1 10.7 6.3

9.7 10.9 13.3 12.0

13.6 10.6 8.7

8.5 11.9

Safety researchers, interested in determining whether the occupancy of a vehicle might be related to the speed at which the vehicle is driven, have observed the following speed (mph) measurements for two random samples of vehicles.

Driver alone 64 50 71 55 67 61 80 56 59 74 at least one

Passenger 44 52 54 48 69 67 54 57 58 51 62 67

a. What are the null and alternative hypotheses for this test?

b. Use ANOVA and the 0.025 level of significance in testing the null hypothesis identified in part (a).

c. For each sample, construct the 95% confidence interval for the population mean.

Alone WithPass

64 44

50 52

71 54

55 48

67 69

61 67

80 54

56 57

59 58

74 51

62

67

Three racqueball players, one from each skill level, have been randomly selected from the membership list of a health club. Using the same ball, each person hits five serves, one with each of five racquets, and using the racquets in a random order. Each serve is clocked with a radar gun, and the results are shown here. With player skill level as a blocking variable, use the 0.025 level of significance in determining whether the treatment effects of the five racquets could all be zero. Using the 0.01 level, evaluate the effectiveness of the blocking variable. Player Skill Level

Beginner Intermed Advance

RacqtA 73 64 83

RacqtB 63 72 89

RacqtC 51 54 72

RacqtD 56 81 86

RacqtE 69 90 97

Given the following data for a two-way ANOVA, identify the sets of null and alternative hypotheses, then use the 0.05 level in testing each null hypothesis.

B1 B2 B3

A1 152 158 160

151 154 160

A2 158 164 152

154 158 155

A3 160 147 147

161 150 146

- business statistics -
**bobpursley**, Sunday, August 9, 2009 at 6:00pmhttp://www.justanswer.com/uploads/Sk1llz/2008-12-18_234257_11.doc

- business statistics -
**PsyDAG**, Monday, August 10, 2009 at 11:49amZ = (mean1 - mean2)/ Sq rt (SD1^2 + SD2^2)

Seek smallest value in table labeled something like "areas under normal distribution."

I hope this helps a little more. Thanks for asking.

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